Prime factorization of $$$956$$$

Find the prime factorization of $$$956$$$.

Start with the number $$$2$$$.

Determine whether $$$956$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$956$$$ by $$${\color{green}2}$$$: $$$\frac{956}{2} = {\color{red}478}$$$.

Determine whether $$$478$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$478$$$ by $$${\color{green}2}$$$: $$$\frac{478}{2} = {\color{red}239}$$$.

The prime number $$${\color{green}239}$$$ has no other factors then $$$1$$$ and $$${\color{green}239}$$$: $$$\frac{239}{239} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$956 = 2^{2} \cdot 239$$$.

The prime factorization is $$$956 = 2^{2} \cdot 239$$$A.