Prime factorization of $$$788$$$

Find the prime factorization of $$$788$$$.

Start with the number $$$2$$$.

Determine whether $$$788$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$788$$$ by $$${\color{green}2}$$$: $$$\frac{788}{2} = {\color{red}394}$$$.

Determine whether $$$394$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$394$$$ by $$${\color{green}2}$$$: $$$\frac{394}{2} = {\color{red}197}$$$.

The prime number $$${\color{green}197}$$$ has no other factors then $$$1$$$ and $$${\color{green}197}$$$: $$$\frac{197}{197} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$788 = 2^{2} \cdot 197$$$.

The prime factorization is $$$788 = 2^{2} \cdot 197$$$A.