Prime factorization of $$$744$$$

Find the prime factorization of $$$744$$$.

Start with the number $$$2$$$.

Determine whether $$$744$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$744$$$ by $$${\color{green}2}$$$: $$$\frac{744}{2} = {\color{red}372}$$$.

Determine whether $$$372$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$372$$$ by $$${\color{green}2}$$$: $$$\frac{372}{2} = {\color{red}186}$$$.

Determine whether $$$186$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$186$$$ by $$${\color{green}2}$$$: $$$\frac{186}{2} = {\color{red}93}$$$.

Determine whether $$$93$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$93$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$93$$$ by $$${\color{green}3}$$$: $$$\frac{93}{3} = {\color{red}31}$$$.

The prime number $$${\color{green}31}$$$ has no other factors then $$$1$$$ and $$${\color{green}31}$$$: $$$\frac{31}{31} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$744 = 2^{3} \cdot 3 \cdot 31$$$.

The prime factorization is $$$744 = 2^{3} \cdot 3 \cdot 31$$$A.