Prime factorization of $$$4383$$$

Find the prime factorization of $$$4383$$$.

Start with the number $$$2$$$.

Determine whether $$$4383$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$4383$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$4383$$$ by $$${\color{green}3}$$$: $$$\frac{4383}{3} = {\color{red}1461}$$$.

Determine whether $$$1461$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$1461$$$ by $$${\color{green}3}$$$: $$$\frac{1461}{3} = {\color{red}487}$$$.

The prime number $$${\color{green}487}$$$ has no other factors then $$$1$$$ and $$${\color{green}487}$$$: $$$\frac{487}{487} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4383 = 3^{2} \cdot 487$$$.

The prime factorization is $$$4383 = 3^{2} \cdot 487$$$A.