Prime factorization of $$$4353$$$

Find the prime factorization of $$$4353$$$.

Start with the number $$$2$$$.

Determine whether $$$4353$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$4353$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$4353$$$ by $$${\color{green}3}$$$: $$$\frac{4353}{3} = {\color{red}1451}$$$.

The prime number $$${\color{green}1451}$$$ has no other factors then $$$1$$$ and $$${\color{green}1451}$$$: $$$\frac{1451}{1451} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4353 = 3 \cdot 1451$$$.

The prime factorization is $$$4353 = 3 \cdot 1451$$$A.