Prime factorization of $$$4197$$$

Find the prime factorization of $$$4197$$$.

Start with the number $$$2$$$.

Determine whether $$$4197$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$4197$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$4197$$$ by $$${\color{green}3}$$$: $$$\frac{4197}{3} = {\color{red}1399}$$$.

The prime number $$${\color{green}1399}$$$ has no other factors then $$$1$$$ and $$${\color{green}1399}$$$: $$$\frac{1399}{1399} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4197 = 3 \cdot 1399$$$.

The prime factorization is $$$4197 = 3 \cdot 1399$$$A.