Prime factorization of $$$3715$$$
Your Input
Find the prime factorization of $$$3715$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3715$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$3715$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$3715$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$3715$$$ by $$${\color{green}5}$$$: $$$\frac{3715}{5} = {\color{red}743}$$$.
The prime number $$${\color{green}743}$$$ has no other factors then $$$1$$$ and $$${\color{green}743}$$$: $$$\frac{743}{743} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3715 = 5 \cdot 743$$$.
Answer
The prime factorization is $$$3715 = 5 \cdot 743$$$A.