# Prime factorization of $3503$

The calculator will find the prime factorization of $3503$, with steps shown.

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Find the prime factorization of $3503$.

### Solution

Start with the number $2$.

Determine whether $3503$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $3503$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $3503$ is divisible by $5$.

Since it is not divisible, move to the next prime number.

The next prime number is $7$.

Determine whether $3503$ is divisible by $7$.

Since it is not divisible, move to the next prime number.

The next prime number is $11$.

Determine whether $3503$ is divisible by $11$.

Since it is not divisible, move to the next prime number.

The next prime number is $13$.

Determine whether $3503$ is divisible by $13$.

Since it is not divisible, move to the next prime number.

The next prime number is $17$.

Determine whether $3503$ is divisible by $17$.

Since it is not divisible, move to the next prime number.

The next prime number is $19$.

Determine whether $3503$ is divisible by $19$.

Since it is not divisible, move to the next prime number.

The next prime number is $23$.

Determine whether $3503$ is divisible by $23$.

Since it is not divisible, move to the next prime number.

The next prime number is $29$.

Determine whether $3503$ is divisible by $29$.

Since it is not divisible, move to the next prime number.

The next prime number is $31$.

Determine whether $3503$ is divisible by $31$.

It is divisible, thus, divide $3503$ by ${\color{green}31}$: $\frac{3503}{31} = {\color{red}113}$.

The prime number ${\color{green}113}$ has no other factors then $1$ and ${\color{green}113}$: $\frac{113}{113} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3503 = 31 \cdot 113$.

The prime factorization is $3503 = 31 \cdot 113$A.