Prime factorization of $$$34$$$

Find the prime factorization of $$$34$$$.

Start with the number $$$2$$$.

Determine whether $$$34$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$34$$$ by $$${\color{green}2}$$$: $$$\frac{34}{2} = {\color{red}17}$$$.

The prime number $$${\color{green}17}$$$ has no other factors then $$$1$$$ and $$${\color{green}17}$$$: $$$\frac{17}{17} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$34 = 2 \cdot 17$$$.

The prime factorization is $$$34 = 2 \cdot 17$$$A.