Prime factorization of $$$3357$$$

Find the prime factorization of $$$3357$$$.

Start with the number $$$2$$$.

Determine whether $$$3357$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$3357$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$3357$$$ by $$${\color{green}3}$$$: $$$\frac{3357}{3} = {\color{red}1119}$$$.

Determine whether $$$1119$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$1119$$$ by $$${\color{green}3}$$$: $$$\frac{1119}{3} = {\color{red}373}$$$.

The prime number $$${\color{green}373}$$$ has no other factors then $$$1$$$ and $$${\color{green}373}$$$: $$$\frac{373}{373} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3357 = 3^{2} \cdot 373$$$.

The prime factorization is $$$3357 = 3^{2} \cdot 373$$$A.