Prime factorization of $$$2673$$$
Your Input
Find the prime factorization of $$$2673$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$2673$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$2673$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$2673$$$ by $$${\color{green}3}$$$: $$$\frac{2673}{3} = {\color{red}891}$$$.
Determine whether $$$891$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$891$$$ by $$${\color{green}3}$$$: $$$\frac{891}{3} = {\color{red}297}$$$.
Determine whether $$$297$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$297$$$ by $$${\color{green}3}$$$: $$$\frac{297}{3} = {\color{red}99}$$$.
Determine whether $$$99$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$99$$$ by $$${\color{green}3}$$$: $$$\frac{99}{3} = {\color{red}33}$$$.
Determine whether $$$33$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$33$$$ by $$${\color{green}3}$$$: $$$\frac{33}{3} = {\color{red}11}$$$.
The prime number $$${\color{green}11}$$$ has no other factors then $$$1$$$ and $$${\color{green}11}$$$: $$$\frac{11}{11} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2673 = 3^{5} \cdot 11$$$.
Answer
The prime factorization is $$$2673 = 3^{5} \cdot 11$$$A.