Prime factorization of $$$267$$$

Find the prime factorization of $$$267$$$.

Start with the number $$$2$$$.

Determine whether $$$267$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$267$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$267$$$ by $$${\color{green}3}$$$: $$$\frac{267}{3} = {\color{red}89}$$$.

The prime number $$${\color{green}89}$$$ has no other factors then $$$1$$$ and $$${\color{green}89}$$$: $$$\frac{89}{89} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$267 = 3 \cdot 89$$$.

The prime factorization is $$$267 = 3 \cdot 89$$$A.