Prime factorization of $$$2445$$$
Your Input
Find the prime factorization of $$$2445$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$2445$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$2445$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$2445$$$ by $$${\color{green}3}$$$: $$$\frac{2445}{3} = {\color{red}815}$$$.
Determine whether $$$815$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$815$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$815$$$ by $$${\color{green}5}$$$: $$$\frac{815}{5} = {\color{red}163}$$$.
The prime number $$${\color{green}163}$$$ has no other factors then $$$1$$$ and $$${\color{green}163}$$$: $$$\frac{163}{163} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2445 = 3 \cdot 5 \cdot 163$$$.
Answer
The prime factorization is $$$2445 = 3 \cdot 5 \cdot 163$$$A.