Prime factorization of $$$2103$$$

Find the prime factorization of $$$2103$$$.

Start with the number $$$2$$$.

Determine whether $$$2103$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$2103$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$2103$$$ by $$${\color{green}3}$$$: $$$\frac{2103}{3} = {\color{red}701}$$$.

The prime number $$${\color{green}701}$$$ has no other factors then $$$1$$$ and $$${\color{green}701}$$$: $$$\frac{701}{701} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2103 = 3 \cdot 701$$$.

The prime factorization is $$$2103 = 3 \cdot 701$$$A.