Prime factorization of $$$1959$$$

Find the prime factorization of $$$1959$$$.

Start with the number $$$2$$$.

Determine whether $$$1959$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$1959$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$1959$$$ by $$${\color{green}3}$$$: $$$\frac{1959}{3} = {\color{red}653}$$$.

The prime number $$${\color{green}653}$$$ has no other factors then $$$1$$$ and $$${\color{green}653}$$$: $$$\frac{653}{653} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1959 = 3 \cdot 653$$$.

The prime factorization is $$$1959 = 3 \cdot 653$$$A.