Prime factorization of $$$1893$$$

Find the prime factorization of $$$1893$$$.

Start with the number $$$2$$$.

Determine whether $$$1893$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$1893$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$1893$$$ by $$${\color{green}3}$$$: $$$\frac{1893}{3} = {\color{red}631}$$$.

The prime number $$${\color{green}631}$$$ has no other factors then $$$1$$$ and $$${\color{green}631}$$$: $$$\frac{631}{631} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1893 = 3 \cdot 631$$$.

The prime factorization is $$$1893 = 3 \cdot 631$$$A.