Prime factorization of $$$1883$$$
Your Input
Find the prime factorization of $$$1883$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$1883$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1883$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$1883$$$ is divisible by $$$5$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$7$$$.
Determine whether $$$1883$$$ is divisible by $$$7$$$.
It is divisible, thus, divide $$$1883$$$ by $$${\color{green}7}$$$: $$$\frac{1883}{7} = {\color{red}269}$$$.
The prime number $$${\color{green}269}$$$ has no other factors then $$$1$$$ and $$${\color{green}269}$$$: $$$\frac{269}{269} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1883 = 7 \cdot 269$$$.
Answer
The prime factorization is $$$1883 = 7 \cdot 269$$$A.