Prime factorization of $$$1822$$$

Find the prime factorization of $$$1822$$$.

Start with the number $$$2$$$.

Determine whether $$$1822$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1822$$$ by $$${\color{green}2}$$$: $$$\frac{1822}{2} = {\color{red}911}$$$.

The prime number $$${\color{green}911}$$$ has no other factors then $$$1$$$ and $$${\color{green}911}$$$: $$$\frac{911}{911} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1822 = 2 \cdot 911$$$.

The prime factorization is $$$1822 = 2 \cdot 911$$$A.