# Prime factorization of $$$1432$$$

### Your Input

**Find the prime factorization of $$$1432$$$.**

### Solution

Start with the number $$$2$$$.

Determine whether $$$1432$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1432$$$ by $$${\color{green}2}$$$: $$$\frac{1432}{2} = {\color{red}716}$$$.

Determine whether $$$716$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$716$$$ by $$${\color{green}2}$$$: $$$\frac{716}{2} = {\color{red}358}$$$.

Determine whether $$$358$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$358$$$ by $$${\color{green}2}$$$: $$$\frac{358}{2} = {\color{red}179}$$$.

The prime number $$${\color{green}179}$$$ has no other factors then $$$1$$$ and $$${\color{green}179}$$$: $$$\frac{179}{179} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1432 = 2^{3} \cdot 179$$$.

### Answer

**The prime factorization is $$$1432 = 2^{3} \cdot 179$$$A.**