RREF of $$$\left[\begin{array}{ccc}1 & 2 & 3\\4 & 1 & 7\end{array}\right]$$$
Related calculators: Gauss-Jordan Elimination Calculator, Matrix Inverse Calculator
Your Input
Find the reduced row echelon form of $$$\left[\begin{array}{ccc}1 & 2 & 3\\4 & 1 & 7\end{array}\right]$$$.
Solution
Subtract row $$$1$$$ multiplied by $$$4$$$ from row $$$2$$$: $$$R_{2} = R_{2} - 4 R_{1}$$$.
$$$\left[\begin{array}{ccc}1 & 2 & 3\\0 & -7 & -5\end{array}\right]$$$
Divide row $$$2$$$ by $$$-7$$$: $$$R_{2} = - \frac{R_{2}}{7}$$$.
$$$\left[\begin{array}{ccc}1 & 2 & 3\\0 & 1 & \frac{5}{7}\end{array}\right]$$$
Subtract row $$$2$$$ multiplied by $$$2$$$ from row $$$1$$$: $$$R_{1} = R_{1} - 2 R_{2}$$$.
$$$\left[\begin{array}{ccc}1 & 0 & \frac{11}{7}\\0 & 1 & \frac{5}{7}\end{array}\right]$$$
Answer
The reduced row echelon form is $$$\left[\begin{array}{ccc}1 & 0 & \frac{11}{7}\\0 & 1 & \frac{5}{7}\end{array}\right]\approx \left[\begin{array}{ccc}1 & 0 & 1.571428571428571\\0 & 1 & 0.714285714285714\end{array}\right].$$$A