RREF of $$$\left[\begin{array}{ccc}1 & 2 & 3\\4 & 1 & 7\end{array}\right]$$$

The calculator will find the reduced row echelon form of the $$$2$$$x$$$3$$$ matrix $$$\left[\begin{array}{ccc}1 & 2 & 3\\4 & 1 & 7\end{array}\right]$$$, with steps shown.

Related calculators: Gauss-Jordan Elimination Calculator, Matrix Inverse Calculator

$$$\times$$$

If the calculator did not compute something or you have identified an error, or you have a suggestion/feedback, please write it in the comments below.

Your Input

Find the reduced row echelon form of $$$\left[\begin{array}{ccc}1 & 2 & 3\\4 & 1 & 7\end{array}\right]$$$.

Solution

Subtract row $$$1$$$ multiplied by $$$4$$$ from row $$$2$$$: $$$R_{2} = R_{2} - 4 R_{1}$$$.

$$$\left[\begin{array}{ccc}1 & 2 & 3\\0 & -7 & -5\end{array}\right]$$$

Divide row $$$2$$$ by $$$-7$$$: $$$R_{2} = - \frac{R_{2}}{7}$$$.

$$$\left[\begin{array}{ccc}1 & 2 & 3\\0 & 1 & \frac{5}{7}\end{array}\right]$$$

Subtract row $$$2$$$ multiplied by $$$2$$$ from row $$$1$$$: $$$R_{1} = R_{1} - 2 R_{2}$$$.

$$$\left[\begin{array}{ccc}1 & 0 & \frac{11}{7}\\0 & 1 & \frac{5}{7}\end{array}\right]$$$

Answer

The reduced row echelon form is $$$\left[\begin{array}{ccc}1 & 0 & \frac{11}{7}\\0 & 1 & \frac{5}{7}\end{array}\right]\approx \left[\begin{array}{ccc}1 & 0 & 1.571428571428571\\0 & 1 & 0.714285714285714\end{array}\right].$$$A