RREF of $$$\left[\begin{array}{cc}0 & 2\\0 & 2\end{array}\right]$$$

The calculator will find the reduced row echelon form of the $$$2$$$x$$$2$$$ matrix $$$\left[\begin{array}{cc}0 & 2\\0 & 2\end{array}\right]$$$, with steps shown.

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Your Input

Find the reduced row echelon form of $$$\left[\begin{array}{cc}0 & 2\\0 & 2\end{array}\right]$$$.

Solution

Since the element at row $$$1$$$ and column $$$1$$$ (pivot element) equals $$$0$$$, we need to swap the rows.

Find the first nonzero element in column $$$1$$$ under the pivot entry.

As can be seen, there are no such entries. Move to the next column.

Divide row $$$1$$$ by $$$2$$$: $$$R_{1} = \frac{R_{1}}{2}$$$.

$$$\left[\begin{array}{cc}0 & 1\\0 & 2\end{array}\right]$$$

Subtract row $$$1$$$ multiplied by $$$2$$$ from row $$$2$$$: $$$R_{2} = R_{2} - 2 R_{1}$$$.

$$$\left[\begin{array}{cc}0 & 1\\0 & 0\end{array}\right]$$$

Answer

The reduced row echelon form is $$$\left[\begin{array}{cc}0 & 1\\0 & 0\end{array}\right]$$$A.