Angle between $\left\langle 7, -3\right\rangle$ and $\left\langle -6, 6\right\rangle$

The calculator will find the angle between the vectors $\left\langle 7, -3\right\rangle$ and $\left\langle -6, 6\right\rangle$, with steps shown.
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Calculate the angle between the vectors $\mathbf{\vec{u}} = \left\langle 7, -3\right\rangle$ and $\mathbf{\vec{v}} = \left\langle -6, 6\right\rangle$.

Solution

First, calculate the dot product: $\mathbf{\vec{u}}\cdot \mathbf{\vec{v}} = -60$ (for steps, see dot product calculator).

Next, find the lengths of the vectors:

$\mathbf{\left\lvert\vec{u}\right\rvert} = \sqrt{58}$ (for steps, see vector length calculator).

$\mathbf{\left\lvert\vec{v}\right\rvert} = 6 \sqrt{2}$ (for steps, see vector length calculator).

Finally, the angle is given by $\cos{\left(\phi \right)} = \frac{\mathbf{\vec{u}}\cdot \mathbf{\vec{v}}}{\mathbf{\left\lvert\vec{u}\right\rvert} \mathbf{\left\lvert\vec{v}\right\rvert}} = \frac{-60}{\left(\sqrt{58}\right)\cdot \left(6 \sqrt{2}\right)} = - \frac{5 \sqrt{29}}{29}$ (in case of complex numbers, we need to take the real part of the dot product).

$\phi = \operatorname{acos}{\left(- \frac{5 \sqrt{29}}{29} \right)} = \left(\frac{180 \operatorname{acos}{\left(- \frac{5 \sqrt{29}}{29} \right)}}{\pi}\right)^0$

$\phi = \operatorname{acos}{\left(- \frac{5 \sqrt{29}}{29} \right)}\approx 2.761086276477428$A
$\phi = \left(\frac{180 \operatorname{acos}{\left(- \frac{5 \sqrt{29}}{29} \right)}}{\pi}\right)^0\approx 158.198590513648188^0$A