Find $$$P{\left(53,6 \right)}$$$
Your Input
Find the number of permutations without repetitions $$$P{\left(53,6 \right)}$$$.
Solution
The formula is $$$P{\left(n,r \right)} = \frac{n!}{\left(n - r\right)!}$$$.
We have that $$$n = 53$$$ and $$$r = 6$$$.
Thus, $$$P{\left(53,6 \right)} = \frac{53!}{\left(53 - 6\right)!} = 16529385600$$$ (for calculating the factorial, see factorial calculator).
Answer
$$$P{\left(53,6 \right)} = 16529385600$$$