Right Endpoint Approximation Calculator for a Function

Approximate the integral $$$\int\limits_{1}^{5} \sqrt{\sin^{5}{\left(x \right)} + 1}\, dx$$$ with $$$n = 4$$$ using the right endpoint approximation.

The right Riemann sum (also known as the right endpoint approximation) uses the right endpoint of a subinterval for computing the height of the approximating rectangle:

$$$\int\limits_{a}^{b} f{\left(x \right)}\, dx\approx \Delta x \left(f{\left(x_{1} \right)} + f{\left(x_{2} \right)} + f{\left(x_{3} \right)}+\dots+f{\left(x_{n-1} \right)} + f{\left(x_{n} \right)}\right)$$$

where $$$\Delta x = \frac{b - a}{n}$$$.

We have that $$$f{\left(x \right)} = \sqrt{\sin^{5}{\left(x \right)} + 1}$$$, $$$a = 1$$$, $$$b = 5$$$, and $$$n = 4$$$.

Therefore, $$$\Delta x = \frac{5 - 1}{4} = 1$$$.

Divide the interval $$$\left[1, 5\right]$$$ into $$$n = 4$$$ subintervals of the length $$$\Delta x = 1$$$ with the following endpoints: $$$a = 1$$$, $$$2$$$, $$$3$$$, $$$4$$$, $$$5 = b$$$.

Now, just evaluate the function at the right endpoints of the subintervals.

$$$f{\left(x_{1} \right)} = f{\left(2 \right)} = \sqrt{\sin^{5}{\left(2 \right)} + 1}\approx 1.273431158532973$$$

$$$f{\left(x_{2} \right)} = f{\left(3 \right)} = \sqrt{\sin^{5}{\left(3 \right)} + 1}\approx 1.000027983813047$$$

$$$f{\left(x_{3} \right)} = f{\left(4 \right)} = \sqrt{\sin^{5}{\left(4 \right)} + 1}\approx 0.867027424870839$$$

$$$f{\left(x_{4} \right)} = f{\left(5 \right)} = \sqrt{\sin^{5}{\left(5 \right)} + 1}\approx 0.434954473370867$$$

Finally, just sum up the above values and multiply by $$$\Delta x = 1$$$: $$$1 \left(1.273431158532973 + 1.000027983813047 + 0.867027424870839 + 0.434954473370867\right) = 3.575441040587726.$$$

$$$\int\limits_{1}^{5} \sqrt{\sin^{5}{\left(x \right)} + 1}\, dx\approx 3.575441040587726$$$A