# Hyperbola Calculator

## Solve hyperbolas step by step

This calculator will find either the equation of the hyperbola from the given parameters or the center, foci, vertices, co-vertices, (semi)major axis length, (semi)minor axis length, latera recta, length of the latera recta (focal width), focal parameter, eccentricity, linear eccentricity (focal distance), directrices, asymptotes, x-intercepts, y-intercepts, domain, and range of the entered hyperbola. Also, it will graph the hyperbola. Steps are available.

Related calculators: Parabola Calculator, Circle Calculator, Ellipse Calculator, Conic Section Calculator

### Your Input

**Find the center, foci, vertices, co-vertices, major axis length, semi-major axis length, minor axis length, semi-minor axis length, latera recta, length of the latera recta (focal width), focal parameter, eccentricity, linear eccentricity (focal distance), directrices, asymptotes, x-intercepts, y-intercepts, domain, and range of the hyperbola $$$x^{2} - 4 y^{2} = 36$$$.**

### Solution

The equation of a hyperbola is $$$\frac{\left(x - h\right)^{2}}{a^{2}} - \frac{\left(y - k\right)^{2}}{b^{2}} = 1$$$, where $$$\left(h, k\right)$$$ is the center, $$$a$$$ and $$$b$$$ are the lengths of the semi-major and the semi-minor axes.

Our hyperbola in this form is $$$\frac{\left(x - 0\right)^{2}}{36} - \frac{\left(y - 0\right)^{2}}{9} = 1$$$.

Thus, $$$h = 0$$$, $$$k = 0$$$, $$$a = 6$$$, $$$b = 3$$$.

The standard form is $$$\frac{x^{2}}{6^{2}} - \frac{y^{2}}{3^{2}} = 1$$$.

The vertex form is $$$\frac{x^{2}}{36} - \frac{y^{2}}{9} = 1$$$.

The general form is $$$x^{2} - 4 y^{2} - 36 = 0$$$.

The linear eccentricity (focal distance) is $$$c = \sqrt{a^{2} + b^{2}} = 3 \sqrt{5}$$$.

The eccentricity is $$$e = \frac{c}{a} = \frac{\sqrt{5}}{2}$$$.

The first focus is $$$\left(h - c, k\right) = \left(- 3 \sqrt{5}, 0\right)$$$.

The second focus is $$$\left(h + c, k\right) = \left(3 \sqrt{5}, 0\right)$$$.

The first vertex is $$$\left(h - a, k\right) = \left(-6, 0\right)$$$.

The second vertex is $$$\left(h + a, k\right) = \left(6, 0\right)$$$.

The first co-vertex is $$$\left(h, k - b\right) = \left(0, -3\right)$$$.

The second co-vertex is $$$\left(h, k + b\right) = \left(0, 3\right)$$$.

The length of the major axis is $$$2 a = 12$$$.

The length of the minor axis is $$$2 b = 6$$$.

The focal parameter is the distance between the focus and the directrix: $$$\frac{b^{2}}{c} = \frac{3 \sqrt{5}}{5}$$$.

The latera recta are the lines parallel to the minor axis that pass through the foci.

The first latus rectum is $$$x = - 3 \sqrt{5}$$$.

The second latus rectum is $$$x = 3 \sqrt{5}$$$.

The endpoints of the first latus rectum can be found by solving the system $$$\begin{cases} x^{2} - 4 y^{2} - 36 = 0 \\ x = - 3 \sqrt{5} \end{cases}$$$ (for steps, see system of equations calculator).

The endpoints of the first latus rectum are $$$\left(- 3 \sqrt{5}, - \frac{3}{2}\right)$$$, $$$\left(- 3 \sqrt{5}, \frac{3}{2}\right)$$$.

The endpoints of the second latus rectum can be found by solving the system $$$\begin{cases} x^{2} - 4 y^{2} - 36 = 0 \\ x = 3 \sqrt{5} \end{cases}$$$ (for steps, see system of equations calculator).

The endpoints of the second latus rectum are $$$\left(3 \sqrt{5}, - \frac{3}{2}\right)$$$, $$$\left(3 \sqrt{5}, \frac{3}{2}\right)$$$.

The length of the latera recta (focal width) is $$$\frac{2 b^{2}}{a} = 3$$$.

The first directrix is $$$x = h - \frac{a^{2}}{c} = - \frac{12 \sqrt{5}}{5}$$$.

The second directrix is $$$x = h + \frac{a^{2}}{c} = \frac{12 \sqrt{5}}{5}$$$.

The first asymptote is $$$y = - \frac{b}{a} \left(x - h\right) + k = - \frac{x}{2}$$$.

The second asymptote is $$$y = \frac{b}{a} \left(x - h\right) + k = \frac{x}{2}$$$.

The x-intercepts can be found by setting $$$y = 0$$$ in the equation and solving for $$$x$$$ (for steps, see intercepts calculator).

x-intercepts: $$$\left(-6, 0\right)$$$, $$$\left(6, 0\right)$$$

The y-intercepts can be found by setting $$$x = 0$$$ in the equation and solving for $$$y$$$: (for steps, see intercepts calculator).

Since there are no real solutions, there are no y-intercepts.

### Answer

**Standard form/equation: $$$\frac{x^{2}}{6^{2}} - \frac{y^{2}}{3^{2}} = 1$$$A.**

**Vertex form/equation: $$$\frac{x^{2}}{36} - \frac{y^{2}}{9} = 1$$$A.**

**General form/equation: $$$x^{2} - 4 y^{2} - 36 = 0$$$A.**

**First focus-directrix form/equation: $$$\left(x + 3 \sqrt{5}\right)^{2} + y^{2} = \frac{5 \left(x + \frac{12 \sqrt{5}}{5}\right)^{2}}{4}$$$A.**

**Second focus-directrix form/equation: $$$\left(x - 3 \sqrt{5}\right)^{2} + y^{2} = \frac{5 \left(x - \frac{12 \sqrt{5}}{5}\right)^{2}}{4}$$$A.**

**Graph: see the graphing calculator.**

**Center: $$$\left(0, 0\right)$$$A.**

**First focus: $$$\left(- 3 \sqrt{5}, 0\right)\approx \left(-6.708203932499369, 0\right)$$$A.**

**Second focus: $$$\left(3 \sqrt{5}, 0\right)\approx \left(6.708203932499369, 0\right)$$$A.**

**First vertex: $$$\left(-6, 0\right)$$$A.**

**Second vertex: $$$\left(6, 0\right)$$$A.**

**First co-vertex: $$$\left(0, -3\right)$$$A.**

**Second co-vertex: $$$\left(0, 3\right)$$$A.**

**Major (transverse) axis length: $$$12$$$A.**

**Semi-major axis length: $$$6$$$A.**

**Minor (conjugate) axis length: $$$6$$$A.**

**Semi-minor axis length: $$$3$$$A.**

**First latus rectum: $$$x = - 3 \sqrt{5}\approx -6.708203932499369$$$A.**

**Second latus rectum: $$$x = 3 \sqrt{5}\approx 6.708203932499369$$$A.**

**Endpoints of the first latus rectum: $$$\left(- 3 \sqrt{5}, - \frac{3}{2}\right)\approx \left(-6.708203932499369, -1.5\right)$$$, $$$\left(- 3 \sqrt{5}, \frac{3}{2}\right)\approx \left(-6.708203932499369, 1.5\right)$$$A.**

**Endpoints of the second latus rectum: $$$\left(3 \sqrt{5}, - \frac{3}{2}\right)\approx \left(6.708203932499369, -1.5\right)$$$, $$$\left(3 \sqrt{5}, \frac{3}{2}\right)\approx \left(6.708203932499369, 1.5\right)$$$A.**

**Length of the latera recta (focal width): $$$3$$$A.**

**Focal parameter: $$$\frac{3 \sqrt{5}}{5}\approx 1.341640786499874$$$A.**

**Eccentricity: $$$\frac{\sqrt{5}}{2}\approx 1.118033988749895$$$A.**

**Linear eccentricity (focal distance): $$$3 \sqrt{5}\approx 6.708203932499369$$$A.**

**First directrix: $$$x = - \frac{12 \sqrt{5}}{5}\approx -5.366563145999495$$$A.**

**Second directrix: $$$x = \frac{12 \sqrt{5}}{5}\approx 5.366563145999495$$$A.**

**First asymptote: $$$y = - \frac{x}{2} = - 0.5 x$$$A.**

**Second asymptote: $$$y = \frac{x}{2} = 0.5 x$$$A.**

**x-intercepts: $$$\left(-6, 0\right)$$$, $$$\left(6, 0\right)$$$A.**

**y-intercepts: no y-intercepts.**

**Domain: $$$\left(-\infty, -6\right] \cup \left[6, \infty\right)$$$A.**

**Range: $$$\left(-\infty, \infty\right)$$$A.**