Determinant of $$$\left[\begin{array}{ccc}-2 & 3 & 1\\7 & -4 & 0\\-3 & 2 & 1\end{array}\right]$$$
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Your Input
Calculate $$$\left|\begin{array}{ccc}-2 & 3 & 1\\7 & -4 & 0\\-3 & 2 & 1\end{array}\right|$$$.
Solution
Subtract row $$$1$$$ from row $$$3$$$: $$$R_{3} = R_{3} - R_{1}$$$.
$$$\left|\begin{array}{ccc}-2 & 3 & 1\\7 & -4 & 0\\-3 & 2 & 1\end{array}\right| = \left|\begin{array}{ccc}-2 & 3 & 1\\7 & -4 & 0\\-1 & -1 & 0\end{array}\right|$$$
Expand along column $$$3$$$:
$$$\left|\begin{array}{ccc}-2 & 3 & 1\\7 & -4 & 0\\-1 & -1 & 0\end{array}\right| = \left(1\right) \left(-1\right)^{1 + 3} \left|\begin{array}{cc}7 & -4\\-1 & -1\end{array}\right| + \left(0\right) \left(-1\right)^{2 + 3} \left|\begin{array}{cc}-2 & 3\\-1 & -1\end{array}\right| + \left(0\right) \left(-1\right)^{3 + 3} \left|\begin{array}{cc}-2 & 3\\7 & -4\end{array}\right| = \left|\begin{array}{cc}7 & -4\\-1 & -1\end{array}\right|$$$
The determinant of a 2x2 matrix is $$$\left|\begin{array}{cc}a & b\\c & d\end{array}\right| = a d - b c$$$.
$$$\left|\begin{array}{cc}7 & -4\\-1 & -1\end{array}\right| = \left(7\right)\cdot \left(-1\right) - \left(-4\right)\cdot \left(-1\right) = -11$$$
Answer
$$$\left|\begin{array}{ccc}-2 & 3 & 1\\7 & -4 & 0\\-3 & 2 & 1\end{array}\right| = -11$$$A