Integral of $$$\frac{x \sin{\left(x \right)}}{2}$$$
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Find $$$\int \frac{x \sin{\left(x \right)}}{2}\, dx$$$.
Solution
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{2}$$$ and $$$f{\left(x \right)} = x \sin{\left(x \right)}$$$:
$${\color{red}{\int{\frac{x \sin{\left(x \right)}}{2} d x}}} = {\color{red}{\left(\frac{\int{x \sin{\left(x \right)} d x}}{2}\right)}}$$
For the integral $$$\int{x \sin{\left(x \right)} d x}$$$, use integration by parts $$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$.
Let $$$\operatorname{u}=x$$$ and $$$\operatorname{dv}=\sin{\left(x \right)} dx$$$.
Then $$$\operatorname{du}=\left(x\right)^{\prime }dx=1 dx$$$ (steps can be seen ») and $$$\operatorname{v}=\int{\sin{\left(x \right)} d x}=- \cos{\left(x \right)}$$$ (steps can be seen »).
The integral becomes
$$\frac{{\color{red}{\int{x \sin{\left(x \right)} d x}}}}{2}=\frac{{\color{red}{\left(x \cdot \left(- \cos{\left(x \right)}\right)-\int{\left(- \cos{\left(x \right)}\right) \cdot 1 d x}\right)}}}{2}=\frac{{\color{red}{\left(- x \cos{\left(x \right)} - \int{\left(- \cos{\left(x \right)}\right)d x}\right)}}}{2}$$
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=-1$$$ and $$$f{\left(x \right)} = \cos{\left(x \right)}$$$:
$$- \frac{x \cos{\left(x \right)}}{2} - \frac{{\color{red}{\int{\left(- \cos{\left(x \right)}\right)d x}}}}{2} = - \frac{x \cos{\left(x \right)}}{2} - \frac{{\color{red}{\left(- \int{\cos{\left(x \right)} d x}\right)}}}{2}$$
The integral of the cosine is $$$\int{\cos{\left(x \right)} d x} = \sin{\left(x \right)}$$$:
$$- \frac{x \cos{\left(x \right)}}{2} + \frac{{\color{red}{\int{\cos{\left(x \right)} d x}}}}{2} = - \frac{x \cos{\left(x \right)}}{2} + \frac{{\color{red}{\sin{\left(x \right)}}}}{2}$$
Therefore,
$$\int{\frac{x \sin{\left(x \right)}}{2} d x} = - \frac{x \cos{\left(x \right)}}{2} + \frac{\sin{\left(x \right)}}{2}$$
Add the constant of integration:
$$\int{\frac{x \sin{\left(x \right)}}{2} d x} = - \frac{x \cos{\left(x \right)}}{2} + \frac{\sin{\left(x \right)}}{2}+C$$
Answer
$$$\int \frac{x \sin{\left(x \right)}}{2}\, dx = \left(- \frac{x \cos{\left(x \right)}}{2} + \frac{\sin{\left(x \right)}}{2}\right) + C$$$A