Integral of $$$v$$$
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Your Input
Find $$$\int v\, dv$$$.
Solution
Apply the power rule $$$\int v^{n}\, dv = \frac{v^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=1$$$:
$${\color{red}{\int{v d v}}}={\color{red}{\frac{v^{1 + 1}}{1 + 1}}}={\color{red}{\left(\frac{v^{2}}{2}\right)}}$$
Therefore,
$$\int{v d v} = \frac{v^{2}}{2}$$
Add the constant of integration:
$$\int{v d v} = \frac{v^{2}}{2}+C$$
Answer
$$$\int v\, dv = \frac{v^{2}}{2} + C$$$A