Integral of $$$p^{6}$$$
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Your Input
Find $$$\int p^{6}\, dp$$$.
Solution
Apply the power rule $$$\int p^{n}\, dp = \frac{p^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=6$$$:
$${\color{red}{\int{p^{6} d p}}}={\color{red}{\frac{p^{1 + 6}}{1 + 6}}}={\color{red}{\left(\frac{p^{7}}{7}\right)}}$$
Therefore,
$$\int{p^{6} d p} = \frac{p^{7}}{7}$$
Add the constant of integration:
$$\int{p^{6} d p} = \frac{p^{7}}{7}+C$$
Answer
$$$\int p^{6}\, dp = \frac{p^{7}}{7} + C$$$A
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