Integral of $$$\frac{m}{98}$$$ with respect to $$$x$$$
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Your Input
Find $$$\int \frac{m}{98}\, dx$$$.
Solution
Apply the constant rule $$$\int c\, dx = c x$$$ with $$$c=\frac{m}{98}$$$:
$${\color{red}{\int{\frac{m}{98} d x}}} = {\color{red}{\left(\frac{m x}{98}\right)}}$$
Therefore,
$$\int{\frac{m}{98} d x} = \frac{m x}{98}$$
Add the constant of integration:
$$\int{\frac{m}{98} d x} = \frac{m x}{98}+C$$
Answer
$$$\int \frac{m}{98}\, dx = \frac{m x}{98} + C$$$A
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