Integral of $$$j_{0} x^{2} x^{s}$$$ with respect to $$$x$$$

Find $$$\int j_{0} x^{2} x^{s}\, dx$$$.

The input is rewritten: $$$\int{j_{0} x^{2} x^{s} d x}=\int{j_{0} x^{s + 2} d x}$$$.

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=j_{0}$$$ and $$$f{\left(x \right)} = x^{s + 2}$$$:

$${\color{red}{\int{j_{0} x^{s + 2} d x}}} = {\color{red}{j_{0} \int{x^{s + 2} d x}}}$$

Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=s + 2$$$:

$$j_{0} {\color{red}{\int{x^{s + 2} d x}}}=j_{0} {\color{red}{\frac{x^{\left(s + 2\right) + 1}}{\left(s + 2\right) + 1}}}=j_{0} {\color{red}{\frac{x^{s + 3}}{s + 3}}}$$

Therefore,

$$\int{j_{0} x^{s + 2} d x} = \frac{j_{0} x^{s + 3}}{s + 3}$$

Add the constant of integration:

$$\int{j_{0} x^{s + 2} d x} = \frac{j_{0} x^{s + 3}}{s + 3}+C$$

$$$\int j_{0} x^{2} x^{s}\, dx = \frac{j_{0} x^{s + 3}}{s + 3} + C$$$A