Integral of $$$\frac{x^{2018}}{e^{\frac{1}{10}}}$$$

Find $$$\int \frac{x^{2018}}{e^{\frac{1}{10}}}\, dx$$$.

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=e^{- \frac{1}{10}}$$$ and $$$f{\left(x \right)} = x^{2018}$$$:

$${\color{red}{\int{\frac{x^{2018}}{e^{\frac{1}{10}}} d x}}} = {\color{red}{\frac{\int{x^{2018} d x}}{e^{\frac{1}{10}}}}}$$

Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=2018$$$:

$$\frac{{\color{red}{\int{x^{2018} d x}}}}{e^{\frac{1}{10}}}=\frac{{\color{red}{\frac{x^{1 + 2018}}{1 + 2018}}}}{e^{\frac{1}{10}}}=\frac{{\color{red}{\left(\frac{x^{2019}}{2019}\right)}}}{e^{\frac{1}{10}}}$$

Therefore,

$$\int{\frac{x^{2018}}{e^{\frac{1}{10}}} d x} = \frac{x^{2019}}{2019 e^{\frac{1}{10}}}$$

Add the constant of integration:

$$\int{\frac{x^{2018}}{e^{\frac{1}{10}}} d x} = \frac{x^{2019}}{2019 e^{\frac{1}{10}}}+C$$

$$$\int \frac{x^{2018}}{e^{\frac{1}{10}}}\, dx = \frac{x^{2019}}{2019 e^{\frac{1}{10}}} + C$$$A