Integral of $$$12 x^{2} \ln\left(x\right)$$$

The calculator will find the integral/antiderivative of $$$12 x^{2} \ln\left(x\right)$$$, with steps shown.

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Find $$$\int 12 x^{2} \ln\left(x\right)\, dx$$$.

Solution

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=12$$$ and $$$f{\left(x \right)} = x^{2} \ln{\left(x \right)}$$$:

$${\color{red}{\int{12 x^{2} \ln{\left(x \right)} d x}}} = {\color{red}{\left(12 \int{x^{2} \ln{\left(x \right)} d x}\right)}}$$

For the integral $$$\int{x^{2} \ln{\left(x \right)} d x}$$$, use integration by parts $$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$.

Let $$$\operatorname{u}=\ln{\left(x \right)}$$$ and $$$\operatorname{dv}=x^{2} dx$$$.

Then $$$\operatorname{du}=\left(\ln{\left(x \right)}\right)^{\prime }dx=\frac{dx}{x}$$$ (steps can be seen ») and $$$\operatorname{v}=\int{x^{2} d x}=\frac{x^{3}}{3}$$$ (steps can be seen »).

So,

$$12 {\color{red}{\int{x^{2} \ln{\left(x \right)} d x}}}=12 {\color{red}{\left(\ln{\left(x \right)} \cdot \frac{x^{3}}{3}-\int{\frac{x^{3}}{3} \cdot \frac{1}{x} d x}\right)}}=12 {\color{red}{\left(\frac{x^{3} \ln{\left(x \right)}}{3} - \int{\frac{x^{2}}{3} d x}\right)}}$$

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{3}$$$ and $$$f{\left(x \right)} = x^{2}$$$:

$$4 x^{3} \ln{\left(x \right)} - 12 {\color{red}{\int{\frac{x^{2}}{3} d x}}} = 4 x^{3} \ln{\left(x \right)} - 12 {\color{red}{\left(\frac{\int{x^{2} d x}}{3}\right)}}$$

Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=2$$$:

$$4 x^{3} \ln{\left(x \right)} - 4 {\color{red}{\int{x^{2} d x}}}=4 x^{3} \ln{\left(x \right)} - 4 {\color{red}{\frac{x^{1 + 2}}{1 + 2}}}=4 x^{3} \ln{\left(x \right)} - 4 {\color{red}{\left(\frac{x^{3}}{3}\right)}}$$

Therefore,

$$\int{12 x^{2} \ln{\left(x \right)} d x} = 4 x^{3} \ln{\left(x \right)} - \frac{4 x^{3}}{3}$$

Simplify:

$$\int{12 x^{2} \ln{\left(x \right)} d x} = x^{3} \left(4 \ln{\left(x \right)} - \frac{4}{3}\right)$$

Add the constant of integration:

$$\int{12 x^{2} \ln{\left(x \right)} d x} = x^{3} \left(4 \ln{\left(x \right)} - \frac{4}{3}\right)+C$$

Answer

$$$\int 12 x^{2} \ln\left(x\right)\, dx = x^{3} \left(4 \ln\left(x\right) - \frac{4}{3}\right) + C$$$A


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