Integral of $$$x^{8}$$$
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Your Input
Find $$$\int x^{8}\, dx$$$.
Solution
Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=8$$$:
$${\color{red}{\int{x^{8} d x}}}={\color{red}{\frac{x^{1 + 8}}{1 + 8}}}={\color{red}{\left(\frac{x^{9}}{9}\right)}}$$
Therefore,
$$\int{x^{8} d x} = \frac{x^{9}}{9}$$
Add the constant of integration:
$$\int{x^{8} d x} = \frac{x^{9}}{9}+C$$
Answer
$$$\int x^{8}\, dx = \frac{x^{9}}{9} + C$$$A