Integral of $$$\frac{\sin{\left(r \right)}}{r}$$$
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Find $$$\int \frac{\sin{\left(r \right)}}{r}\, dr$$$.
Solution
This integral (Sine Integral) does not have a closed form:
$${\color{red}{\int{\frac{\sin{\left(r \right)}}{r} d r}}} = {\color{red}{\operatorname{Si}{\left(r \right)}}}$$
Therefore,
$$\int{\frac{\sin{\left(r \right)}}{r} d r} = \operatorname{Si}{\left(r \right)}$$
Add the constant of integration:
$$\int{\frac{\sin{\left(r \right)}}{r} d r} = \operatorname{Si}{\left(r \right)}+C$$
Answer
$$$\int \frac{\sin{\left(r \right)}}{r}\, dr = \operatorname{Si}{\left(r \right)} + C$$$A