Integral of $$$\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$$ with respect to $$$x$$$

The calculator will find the integral/antiderivative of $$$\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$$ with respect to $$$x$$$, with steps shown.

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Find $$$\int \frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}\, dx$$$.

Solution

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$$ and $$$f{\left(x \right)} = \sin{\left(5 x \right)}$$$:

$${\color{red}{\int{\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} d x}}} = {\color{red}{\left(\frac{\int{\sin{\left(5 x \right)} d x}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}\right)}}$$

Let $$$u=5 x$$$.

Then $$$du=\left(5 x\right)^{\prime }dx = 5 dx$$$ (steps can be seen »), and we have that $$$dx = \frac{du}{5}$$$.

Therefore,

$$\frac{{\color{red}{\int{\sin{\left(5 x \right)} d x}}}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} = \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{5} d u}}}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$

Apply the constant multiple rule $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ with $$$c=\frac{1}{5}$$$ and $$$f{\left(u \right)} = \sin{\left(u \right)}$$$:

$$\frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{5} d u}}}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} = \frac{{\color{red}{\left(\frac{\int{\sin{\left(u \right)} d u}}{5}\right)}}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}$$

The integral of the sine is $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:

$$\frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{10 \sin{\left(\frac{x_{0}}{5} \right)}} = \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{10 \sin{\left(\frac{x_{0}}{5} \right)}}$$

Recall that $$$u=5 x$$$:

$$- \frac{\cos{\left({\color{red}{u}} \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}} = - \frac{\cos{\left({\color{red}{\left(5 x\right)}} \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}}$$

Therefore,

$$\int{\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} d x} = - \frac{\cos{\left(5 x \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}}$$

Add the constant of integration:

$$\int{\frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}} d x} = - \frac{\cos{\left(5 x \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}}+C$$

Answer

$$$\int \frac{\sin{\left(5 x \right)}}{2 \sin{\left(\frac{x_{0}}{5} \right)}}\, dx = - \frac{\cos{\left(5 x \right)}}{10 \sin{\left(\frac{x_{0}}{5} \right)}} + C$$$A


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