Integral of $$$\sin{\left(x \right)} + 18$$$
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Find $$$\int \left(\sin{\left(x \right)} + 18\right)\, dx$$$.
Solution
Integrate term by term:
$${\color{red}{\int{\left(\sin{\left(x \right)} + 18\right)d x}}} = {\color{red}{\left(\int{18 d x} + \int{\sin{\left(x \right)} d x}\right)}}$$
Apply the constant rule $$$\int c\, dx = c x$$$ with $$$c=18$$$:
$$\int{\sin{\left(x \right)} d x} + {\color{red}{\int{18 d x}}} = \int{\sin{\left(x \right)} d x} + {\color{red}{\left(18 x\right)}}$$
The integral of the sine is $$$\int{\sin{\left(x \right)} d x} = - \cos{\left(x \right)}$$$:
$$18 x + {\color{red}{\int{\sin{\left(x \right)} d x}}} = 18 x + {\color{red}{\left(- \cos{\left(x \right)}\right)}}$$
Therefore,
$$\int{\left(\sin{\left(x \right)} + 18\right)d x} = 18 x - \cos{\left(x \right)}$$
Add the constant of integration:
$$\int{\left(\sin{\left(x \right)} + 18\right)d x} = 18 x - \cos{\left(x \right)}+C$$
Answer
$$$\int \left(\sin{\left(x \right)} + 18\right)\, dx = \left(18 x - \cos{\left(x \right)}\right) + C$$$A