Integral of $$$\frac{\ln\left(1 - x\right) \ln^{2}\left(x + 1\right)}{x + 1}$$$
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Find $$$\int \frac{\ln\left(1 - x\right) \ln^{2}\left(x + 1\right)}{x + 1}\, dx$$$.
Related calculator: Definite and Improper Integral Calculator
Find $$$\int \frac{\ln\left(1 - x\right) \ln^{2}\left(x + 1\right)}{x + 1}\, dx$$$.