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Integral of $$$\frac{\ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)}{x \left(x + 1\right)^{2}}$$$

The calculator will find the integral/antiderivative of $$$\frac{\ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)}{x \left(x + 1\right)^{2}}$$$, with steps shown.

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Find $$$\int \frac{\ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)}{x \left(x + 1\right)^{2}}\, dx$$$.

Related Notes: Substitution (Change of Variable) Rule , Integration by Parts , Concept of Antiderivative and Indefinite Integral , Integrals Involving Trig Functions , Trigonometric Substitutions In Integrals , Integrals Involving Rational Functions , Integration Formulas (Table of Indefinite Integrals) , Properties of Indefinite Integrals , Table of Antiderivatives