Integral of $$$\ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)$$$

The calculator will find the integral/antiderivative of $$$\ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)$$$, with steps shown.

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Find $$$\int \ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)\, dx$$$.