Integral of $$$\ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)$$$
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Find $$$\int \ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)\, dx$$$.
Related calculator: Definite and Improper Integral Calculator
Find $$$\int \ln\left(\frac{1 - x}{x + 1}\right) \ln\left(\frac{2}{x + 1}\right)\, dx$$$.