Integral of $$$e^{\frac{1}{x}}$$$ with respect to $$$y$$$
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Your Input
Find $$$\int e^{\frac{1}{x}}\, dy$$$.
Solution
Apply the constant rule $$$\int c\, dy = c y$$$ with $$$c=e^{\frac{1}{x}}$$$:
$${\color{red}{\int{e^{\frac{1}{x}} d y}}} = {\color{red}{y e^{\frac{1}{x}}}}$$
Therefore,
$$\int{e^{\frac{1}{x}} d y} = y e^{\frac{1}{x}}$$
Add the constant of integration:
$$\int{e^{\frac{1}{x}} d y} = y e^{\frac{1}{x}}+C$$
Answer
$$$\int e^{\frac{1}{x}}\, dy = y e^{\frac{1}{x}} + C$$$A