Integral of $$$\frac{1}{b}$$$ with respect to $$$t$$$
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Your Input
Find $$$\int \frac{1}{b}\, dt$$$.
Solution
Apply the constant rule $$$\int c\, dt = c t$$$ with $$$c=\frac{1}{b}$$$:
$${\color{red}{\int{\frac{1}{b} d t}}} = {\color{red}{\frac{t}{b}}}$$
Therefore,
$$\int{\frac{1}{b} d t} = \frac{t}{b}$$
Add the constant of integration:
$$\int{\frac{1}{b} d t} = \frac{t}{b}+C$$
Answer
$$$\int \frac{1}{b}\, dt = \frac{t}{b} + C$$$A
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