Integral of $$$\frac{\sqrt{6}}{2}$$$ with respect to $$$r$$$

The calculator will find the integral/antiderivative of $$$\frac{\sqrt{6}}{2}$$$ with respect to $$$r$$$, with steps shown.

Find $$$\int \frac{\sqrt{6}}{2}\, dr$$$.

Apply the constant rule $$$\int c\, dr = c r$$$ with $$$c=\frac{\sqrt{6}}{2}$$$:

$${\color{red}{\int{\frac{\sqrt{6}}{2} d r}}} = {\color{red}{\left(\frac{\sqrt{6} r}{2}\right)}}$$

Therefore,

$$\int{\frac{\sqrt{6}}{2} d r} = \frac{\sqrt{6} r}{2}$$

Add the constant of integration:

$$\int{\frac{\sqrt{6}}{2} d r} = \frac{\sqrt{6} r}{2}+C$$

$$$\int \frac{\sqrt{6}}{2}\, dr = \frac{\sqrt{6} r}{2} + C$$$A