Integral of $$$\frac{6}{x^{2} - 22 x}$$$
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Find $$$\int \frac{6}{x^{2} - 22 x}\, dx$$$.
Solution
Simplify the integrand:
$${\color{red}{\int{\frac{6}{x^{2} - 22 x} d x}}} = {\color{red}{\int{\frac{6}{x \left(x - 22\right)} d x}}}$$
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=6$$$ and $$$f{\left(x \right)} = \frac{1}{x \left(x - 22\right)}$$$:
$${\color{red}{\int{\frac{6}{x \left(x - 22\right)} d x}}} = {\color{red}{\left(6 \int{\frac{1}{x \left(x - 22\right)} d x}\right)}}$$
Perform partial fraction decomposition (steps can be seen »):
$$6 {\color{red}{\int{\frac{1}{x \left(x - 22\right)} d x}}} = 6 {\color{red}{\int{\left(\frac{1}{22 \left(x - 22\right)} - \frac{1}{22 x}\right)d x}}}$$
Integrate term by term:
$$6 {\color{red}{\int{\left(\frac{1}{22 \left(x - 22\right)} - \frac{1}{22 x}\right)d x}}} = 6 {\color{red}{\left(- \int{\frac{1}{22 x} d x} + \int{\frac{1}{22 \left(x - 22\right)} d x}\right)}}$$
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{22}$$$ and $$$f{\left(x \right)} = \frac{1}{x}$$$:
$$6 \int{\frac{1}{22 \left(x - 22\right)} d x} - 6 {\color{red}{\int{\frac{1}{22 x} d x}}} = 6 \int{\frac{1}{22 \left(x - 22\right)} d x} - 6 {\color{red}{\left(\frac{\int{\frac{1}{x} d x}}{22}\right)}}$$
The integral of $$$\frac{1}{x}$$$ is $$$\int{\frac{1}{x} d x} = \ln{\left(\left|{x}\right| \right)}$$$:
$$6 \int{\frac{1}{22 \left(x - 22\right)} d x} - \frac{3 {\color{red}{\int{\frac{1}{x} d x}}}}{11} = 6 \int{\frac{1}{22 \left(x - 22\right)} d x} - \frac{3 {\color{red}{\ln{\left(\left|{x}\right| \right)}}}}{11}$$
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{22}$$$ and $$$f{\left(x \right)} = \frac{1}{x - 22}$$$:
$$- \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + 6 {\color{red}{\int{\frac{1}{22 \left(x - 22\right)} d x}}} = - \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + 6 {\color{red}{\left(\frac{\int{\frac{1}{x - 22} d x}}{22}\right)}}$$
Let $$$u=x - 22$$$.
Then $$$du=\left(x - 22\right)^{\prime }dx = 1 dx$$$ (steps can be seen »), and we have that $$$dx = du$$$.
The integral becomes
$$- \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + \frac{3 {\color{red}{\int{\frac{1}{x - 22} d x}}}}{11} = - \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + \frac{3 {\color{red}{\int{\frac{1}{u} d u}}}}{11}$$
The integral of $$$\frac{1}{u}$$$ is $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:
$$- \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + \frac{3 {\color{red}{\int{\frac{1}{u} d u}}}}{11} = - \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + \frac{3 {\color{red}{\ln{\left(\left|{u}\right| \right)}}}}{11}$$
Recall that $$$u=x - 22$$$:
$$- \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + \frac{3 \ln{\left(\left|{{\color{red}{u}}}\right| \right)}}{11} = - \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + \frac{3 \ln{\left(\left|{{\color{red}{\left(x - 22\right)}}}\right| \right)}}{11}$$
Therefore,
$$\int{\frac{6}{x^{2} - 22 x} d x} = - \frac{3 \ln{\left(\left|{x}\right| \right)}}{11} + \frac{3 \ln{\left(\left|{x - 22}\right| \right)}}{11}$$
Simplify:
$$\int{\frac{6}{x^{2} - 22 x} d x} = \frac{3 \left(- \ln{\left(\left|{x}\right| \right)} + \ln{\left(\left|{x - 22}\right| \right)}\right)}{11}$$
Add the constant of integration:
$$\int{\frac{6}{x^{2} - 22 x} d x} = \frac{3 \left(- \ln{\left(\left|{x}\right| \right)} + \ln{\left(\left|{x - 22}\right| \right)}\right)}{11}+C$$
Answer
$$$\int \frac{6}{x^{2} - 22 x}\, dx = \frac{3 \left(- \ln\left(\left|{x}\right|\right) + \ln\left(\left|{x - 22}\right|\right)\right)}{11} + C$$$A