Integral of $$$28 x \sin{\left(3 \right)} \cos{\left(7 x \right)}$$$

The calculator will find the integral/antiderivative of $$$28 x \sin{\left(3 \right)} \cos{\left(7 x \right)}$$$, with steps shown.

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Your Input

Find $$$\int 28 x \sin{\left(3 \right)} \cos{\left(7 x \right)}\, dx$$$.

The trigonometric functions expect the argument in radians. To enter the argument in degrees, multiply it by pi/180, e.g. write 45° as 45*pi/180, or use the appropriate function adding 'd', e.g. write sin(45°) as sind(45).

Solution

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=28 \sin{\left(3 \right)}$$$ and $$$f{\left(x \right)} = x \cos{\left(7 x \right)}$$$:

$${\color{red}{\int{28 x \sin{\left(3 \right)} \cos{\left(7 x \right)} d x}}} = {\color{red}{\left(28 \sin{\left(3 \right)} \int{x \cos{\left(7 x \right)} d x}\right)}}$$

For the integral $$$\int{x \cos{\left(7 x \right)} d x}$$$, use integration by parts $$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$.

Let $$$\operatorname{u}=x$$$ and $$$\operatorname{dv}=\cos{\left(7 x \right)} dx$$$.

Then $$$\operatorname{du}=\left(x\right)^{\prime }dx=1 dx$$$ (steps can be seen ») and $$$\operatorname{v}=\int{\cos{\left(7 x \right)} d x}=\frac{\sin{\left(7 x \right)}}{7}$$$ (steps can be seen »).

Therefore,

$$28 \sin{\left(3 \right)} {\color{red}{\int{x \cos{\left(7 x \right)} d x}}}=28 \sin{\left(3 \right)} {\color{red}{\left(x \cdot \frac{\sin{\left(7 x \right)}}{7}-\int{\frac{\sin{\left(7 x \right)}}{7} \cdot 1 d x}\right)}}=28 \sin{\left(3 \right)} {\color{red}{\left(\frac{x \sin{\left(7 x \right)}}{7} - \int{\frac{\sin{\left(7 x \right)}}{7} d x}\right)}}$$

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{7}$$$ and $$$f{\left(x \right)} = \sin{\left(7 x \right)}$$$:

$$28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} - {\color{red}{\int{\frac{\sin{\left(7 x \right)}}{7} d x}}}\right) = 28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} - {\color{red}{\left(\frac{\int{\sin{\left(7 x \right)} d x}}{7}\right)}}\right)$$

Let $$$u=7 x$$$.

Then $$$du=\left(7 x\right)^{\prime }dx = 7 dx$$$ (steps can be seen »), and we have that $$$dx = \frac{du}{7}$$$.

Thus,

$$28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} - \frac{{\color{red}{\int{\sin{\left(7 x \right)} d x}}}}{7}\right) = 28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{7} d u}}}}{7}\right)$$

Apply the constant multiple rule $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ with $$$c=\frac{1}{7}$$$ and $$$f{\left(u \right)} = \sin{\left(u \right)}$$$:

$$28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{7} d u}}}}{7}\right) = 28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} - \frac{{\color{red}{\left(\frac{\int{\sin{\left(u \right)} d u}}{7}\right)}}}{7}\right)$$

The integral of the sine is $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:

$$28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} - \frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{49}\right) = 28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} - \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{49}\right)$$

Recall that $$$u=7 x$$$:

$$28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} + \frac{\cos{\left({\color{red}{u}} \right)}}{49}\right) = 28 \sin{\left(3 \right)} \left(\frac{x \sin{\left(7 x \right)}}{7} + \frac{\cos{\left({\color{red}{\left(7 x\right)}} \right)}}{49}\right)$$

Therefore,

$$\int{28 x \sin{\left(3 \right)} \cos{\left(7 x \right)} d x} = 28 \left(\frac{x \sin{\left(7 x \right)}}{7} + \frac{\cos{\left(7 x \right)}}{49}\right) \sin{\left(3 \right)}$$

Simplify:

$$\int{28 x \sin{\left(3 \right)} \cos{\left(7 x \right)} d x} = \frac{4 \left(7 x \sin{\left(7 x \right)} + \cos{\left(7 x \right)}\right) \sin{\left(3 \right)}}{7}$$

Add the constant of integration:

$$\int{28 x \sin{\left(3 \right)} \cos{\left(7 x \right)} d x} = \frac{4 \left(7 x \sin{\left(7 x \right)} + \cos{\left(7 x \right)}\right) \sin{\left(3 \right)}}{7}+C$$

Answer

$$$\int 28 x \sin{\left(3 \right)} \cos{\left(7 x \right)}\, dx = \frac{4 \left(7 x \sin{\left(7 x \right)} + \cos{\left(7 x \right)}\right) \sin{\left(3 \right)}}{7} + C$$$A


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