Integral of $$$\frac{13 x^{2} \cos{\left(1 \right)}}{2}$$$
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Find $$$\int \frac{13 x^{2} \cos{\left(1 \right)}}{2}\, dx$$$.
Solution
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{13 \cos{\left(1 \right)}}{2}$$$ and $$$f{\left(x \right)} = x^{2}$$$:
$${\color{red}{\int{\frac{13 x^{2} \cos{\left(1 \right)}}{2} d x}}} = {\color{red}{\left(\frac{13 \cos{\left(1 \right)} \int{x^{2} d x}}{2}\right)}}$$
Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=2$$$:
$$\frac{13 \cos{\left(1 \right)} {\color{red}{\int{x^{2} d x}}}}{2}=\frac{13 \cos{\left(1 \right)} {\color{red}{\frac{x^{1 + 2}}{1 + 2}}}}{2}=\frac{13 \cos{\left(1 \right)} {\color{red}{\left(\frac{x^{3}}{3}\right)}}}{2}$$
Therefore,
$$\int{\frac{13 x^{2} \cos{\left(1 \right)}}{2} d x} = \frac{13 x^{3} \cos{\left(1 \right)}}{6}$$
Add the constant of integration:
$$\int{\frac{13 x^{2} \cos{\left(1 \right)}}{2} d x} = \frac{13 x^{3} \cos{\left(1 \right)}}{6}+C$$
Answer
$$$\int \frac{13 x^{2} \cos{\left(1 \right)}}{2}\, dx = \frac{13 x^{3} \cos{\left(1 \right)}}{6} + C$$$A