Integral of $$$\frac{1}{12 x}$$$

Find $$$\int \frac{1}{12 x}\, dx$$$.

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{12}$$$ and $$$f{\left(x \right)} = \frac{1}{x}$$$:

$${\color{red}{\int{\frac{1}{12 x} d x}}} = {\color{red}{\left(\frac{\int{\frac{1}{x} d x}}{12}\right)}}$$

The integral of $$$\frac{1}{x}$$$ is $$$\int{\frac{1}{x} d x} = \ln{\left(\left|{x}\right| \right)}$$$:

$$\frac{{\color{red}{\int{\frac{1}{x} d x}}}}{12} = \frac{{\color{red}{\ln{\left(\left|{x}\right| \right)}}}}{12}$$

Therefore,

$$\int{\frac{1}{12 x} d x} = \frac{\ln{\left(\left|{x}\right| \right)}}{12}$$

Add the constant of integration:

$$\int{\frac{1}{12 x} d x} = \frac{\ln{\left(\left|{x}\right| \right)}}{12}+C$$

$$$\int \frac{1}{12 x}\, dx = \frac{\ln\left(\left|{x}\right|\right)}{12} + C$$$A