Integral of $$$x^{4} - 7 x^{2} - 1$$$

Find $$$\int \left(x^{4} - 7 x^{2} - 1\right)\, dx$$$.

Integrate term by term:

$${\color{red}{\int{\left(x^{4} - 7 x^{2} - 1\right)d x}}} = {\color{red}{\left(- \int{1 d x} - \int{7 x^{2} d x} + \int{x^{4} d x}\right)}}$$

Apply the constant rule $$$\int c\, dx = c x$$$ with $$$c=1$$$:

$$- \int{7 x^{2} d x} + \int{x^{4} d x} - {\color{red}{\int{1 d x}}} = - \int{7 x^{2} d x} + \int{x^{4} d x} - {\color{red}{x}}$$

Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=4$$$:

$$- x - \int{7 x^{2} d x} + {\color{red}{\int{x^{4} d x}}}=- x - \int{7 x^{2} d x} + {\color{red}{\frac{x^{1 + 4}}{1 + 4}}}=- x - \int{7 x^{2} d x} + {\color{red}{\left(\frac{x^{5}}{5}\right)}}$$

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=7$$$ and $$$f{\left(x \right)} = x^{2}$$$:

$$\frac{x^{5}}{5} - x - {\color{red}{\int{7 x^{2} d x}}} = \frac{x^{5}}{5} - x - {\color{red}{\left(7 \int{x^{2} d x}\right)}}$$

Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=2$$$:

$$\frac{x^{5}}{5} - x - 7 {\color{red}{\int{x^{2} d x}}}=\frac{x^{5}}{5} - x - 7 {\color{red}{\frac{x^{1 + 2}}{1 + 2}}}=\frac{x^{5}}{5} - x - 7 {\color{red}{\left(\frac{x^{3}}{3}\right)}}$$

Therefore,

$$\int{\left(x^{4} - 7 x^{2} - 1\right)d x} = \frac{x^{5}}{5} - \frac{7 x^{3}}{3} - x$$

Add the constant of integration:

$$\int{\left(x^{4} - 7 x^{2} - 1\right)d x} = \frac{x^{5}}{5} - \frac{7 x^{3}}{3} - x+C$$

$$$\int \left(x^{4} - 7 x^{2} - 1\right)\, dx = \left(\frac{x^{5}}{5} - \frac{7 x^{3}}{3} - x\right) + C$$$A