Integral of $$$\frac{\ln^{3}\left(1 - x^{2}\right)}{x + 1}$$$
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Find $$$\int \frac{\ln^{3}\left(1 - x^{2}\right)}{x + 1}\, dx$$$.
Related calculator: Definite and Improper Integral Calculator
Find $$$\int \frac{\ln^{3}\left(1 - x^{2}\right)}{x + 1}\, dx$$$.