Integral of $$$- 6 e x^{2} - 2 x$$$
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Find $$$\int \left(- 6 e x^{2} - 2 x\right)\, dx$$$.
Solution
Integrate term by term:
$${\color{red}{\int{\left(- 6 e x^{2} - 2 x\right)d x}}} = {\color{red}{\left(- \int{2 x d x} - \int{6 e x^{2} d x}\right)}}$$
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=2$$$ and $$$f{\left(x \right)} = x$$$:
$$- \int{6 e x^{2} d x} - {\color{red}{\int{2 x d x}}} = - \int{6 e x^{2} d x} - {\color{red}{\left(2 \int{x d x}\right)}}$$
Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=1$$$:
$$- \int{6 e x^{2} d x} - 2 {\color{red}{\int{x d x}}}=- \int{6 e x^{2} d x} - 2 {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=- \int{6 e x^{2} d x} - 2 {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=6 e$$$ and $$$f{\left(x \right)} = x^{2}$$$:
$$- x^{2} - {\color{red}{\int{6 e x^{2} d x}}} = - x^{2} - {\color{red}{\left(6 e \int{x^{2} d x}\right)}}$$
Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=2$$$:
$$- x^{2} - 6 e {\color{red}{\int{x^{2} d x}}}=- x^{2} - 6 e {\color{red}{\frac{x^{1 + 2}}{1 + 2}}}=- x^{2} - 6 e {\color{red}{\left(\frac{x^{3}}{3}\right)}}$$
Therefore,
$$\int{\left(- 6 e x^{2} - 2 x\right)d x} = - 2 e x^{3} - x^{2}$$
Simplify:
$$\int{\left(- 6 e x^{2} - 2 x\right)d x} = x^{2} \left(- 2 e x - 1\right)$$
Add the constant of integration:
$$\int{\left(- 6 e x^{2} - 2 x\right)d x} = x^{2} \left(- 2 e x - 1\right)+C$$
Answer
$$$\int \left(- 6 e x^{2} - 2 x\right)\, dx = x^{2} \left(- 2 e x - 1\right) + C$$$A